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I can't get to play the video #132

@EgorBlagodarov

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@EgorBlagodarov

Hello! I am writing a program to conduct a video broadcast from the camera. I decided to transmit data via RTSP. Requests are sent to the server and responses begin to arrive, after receiving, I translate the Frame into a byte[] array and try to convert it to a bitmap, but it gives an error. Can you tell me how I can make a broadcast?

public static async void RTSPClient(CancellationToken token)
{
//параметры и запросы
var serverUri = new Uri("rtsp://192.168.0.94:554/cam0_0");
var credentials = new NetworkCredential("root", "root");
var connectionParameters = new ConnectionParameters(serverUri, credentials);
connectionParameters.RtpTransport = RtpTransportProtocol.TCP;

RtspClient rtspCl1 = new RtspClient(connectionParameters);
try
{
await rtspCl1.ConnectAsync(token);

              //the process of obtaining frames
              rtspCl1.FrameReceived += (sender, frame) =>
              {
              
              switch (frame)
              {
                            case RawH264IFrame h264IFrame:
                            Console.WriteLine("Формат RawH264IFrame");
                            
                            //the process of obtaining frames
                            byte[] cv1 = frame.FrameSegment.Array;
                            MemoryStream memoryStream = new MemoryStream(fileBytes);
                            
                            //an error pops up here, the obviously received array is not an image, although the format is RawH264IFrame
                            Bitmap bitmap = new Bitmap(memoryStream);
                            
                            break;
                            
                            default:
                            Console.WriteLine("Формат неизвестен");
                            break;
              }

};

await rtspCl1.ReceiveAsync(token);

}
catch (SocketException ex)
{
Console.WriteLine("Подключение не установлено");
Console.WriteLine("Код ошибки:");
Console.WriteLine(ex.Message);

}
}

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