Sync LeetCode submission Runtime - 490 ms (47.23%), Memory - 51.7 MB (52.51%)

Author: DhanushNehru

0079-word-search/README.md

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+<p>Given an <code>m x n</code> grid of characters <code>board</code> and a string <code>word</code>, return <code>true</code> <em>if</em> <code>word</code> <em>exists in the grid</em>.</p>
+
+<p>The word can be constructed from letters of sequentially adjacent cells, where adjacent cells are horizontally or vertically neighboring. The same letter cell may not be used more than once.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+<img alt="" src="https://assets.leetcode.com/uploads/2020/11/04/word2.jpg" style="width: 322px; height: 242px;" />
+<pre>
+<strong>Input:</strong> board = [[&quot;A&quot;,&quot;B&quot;,&quot;C&quot;,&quot;E&quot;],[&quot;S&quot;,&quot;F&quot;,&quot;C&quot;,&quot;S&quot;],[&quot;A&quot;,&quot;D&quot;,&quot;E&quot;,&quot;E&quot;]], word = &quot;ABCCED&quot;
+<strong>Output:</strong> true
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+<img alt="" src="https://assets.leetcode.com/uploads/2020/11/04/word-1.jpg" style="width: 322px; height: 242px;" />
+<pre>
+<strong>Input:</strong> board = [[&quot;A&quot;,&quot;B&quot;,&quot;C&quot;,&quot;E&quot;],[&quot;S&quot;,&quot;F&quot;,&quot;C&quot;,&quot;S&quot;],[&quot;A&quot;,&quot;D&quot;,&quot;E&quot;,&quot;E&quot;]], word = &quot;SEE&quot;
+<strong>Output:</strong> true
+</pre>
+
+<p><strong class="example">Example 3:</strong></p>
+<img alt="" src="https://assets.leetcode.com/uploads/2020/10/15/word3.jpg" style="width: 322px; height: 242px;" />
+<pre>
+<strong>Input:</strong> board = [[&quot;A&quot;,&quot;B&quot;,&quot;C&quot;,&quot;E&quot;],[&quot;S&quot;,&quot;F&quot;,&quot;C&quot;,&quot;S&quot;],[&quot;A&quot;,&quot;D&quot;,&quot;E&quot;,&quot;E&quot;]], word = &quot;ABCB&quot;
+<strong>Output:</strong> false
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>m == board.length</code></li>
+	<li><code>n = board[i].length</code></li>
+	<li><code>1 &lt;= m, n &lt;= 6</code></li>
+	<li><code>1 &lt;= word.length &lt;= 15</code></li>
+	<li><code>board</code> and <code>word</code> consists of only lowercase and uppercase English letters.</li>
+</ul>
+
+<p>&nbsp;</p>
+<p><strong>Follow up:</strong> Could you use search pruning to make your solution faster with a larger <code>board</code>?</p>

0079-word-search/solution.js

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+/**
+ * @param {character[][]} board
+ * @param {string} word
+ * @return {boolean}
+ */
+var exist = function(board, word) {
+    const mLength = board.length
+
+    if(mLength == 0){
+        return false;
+    }
+
+    const nLength = board[0].length
+
+    const directions = [[-1, 0], [0, 1], [1, 0], [0, -1]];
+
+    const check = (x,y,k) => {
+        if (board[x][y] !== word[k]) return false;
+        if (k === word.length - 1) return true;
+
+        board[x][y] = '*'; // mark it as visited
+
+        for (const [dx, dy] of directions) {
+            const i = x + dx;
+            const j = y + dy;
+            if (i >= 0 && i < mLength && j >= 0 && j < nLength) {
+                if (check(i, j, k + 1)) return true;
+            }
+        }
+
+        board[x][y] = word[k]; // reset the value
+        return false;
+    }
+
+    for(let i=0;i<mLength;i++){
+        for(let j=0;j<nLength;j++){
+            console.log(" I ", i , " J ", j)
+            if(check(i,j,0)){
+                return true;
+            }
+        }
+    }
+
+    return false;
+};