Sync LeetCode submission Runtime - 1469 ms (9.17%), Memory - 0B (100.00%)

Author: DhanushNehru

0181-employees-earning-more-than-their-managers/README.md

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+<p>Table: <code>Employee</code></p>
+
+<pre>
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| id          | int     |
+| name        | varchar |
+| salary      | int     |
+| managerId   | int     |
++-------------+---------+
+id is the primary key (column with unique values) for this table.
+Each row of this table indicates the ID of an employee, their name, salary, and the ID of their manager.
+</pre>
+
+<p>&nbsp;</p>
+
+<p>Write a solution&nbsp;to find the employees who earn more than their managers.</p>
+
+<p>Return the result table in <strong>any order</strong>.</p>
+
+<p>The result format is in the following example.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> 
+Employee table:
++----+-------+--------+-----------+
+| id | name  | salary | managerId |
++----+-------+--------+-----------+
+| 1  | Joe   | 70000  | 3         |
+| 2  | Henry | 80000  | 4         |
+| 3  | Sam   | 60000  | Null      |
+| 4  | Max   | 90000  | Null      |
++----+-------+--------+-----------+
+<strong>Output:</strong> 
++----------+
+| Employee |
++----------+
+| Joe      |
++----------+
+<strong>Explanation:</strong> Joe is the only employee who earns more than his manager.
+</pre>

0181-employees-earning-more-than-their-managers/solution.sql

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+# Write your MySQL query statement below
+SELECT name AS Employee FROM Employee 
+WHERE Employee.salary > ( 
+    SELECT Salary FROM Employee AS Employee2 
+    WHERE Employee2.id = Employee.managerId
+);