Determine speed limit for route

[parsispresswala]

Hello guys,

I'm trying to find a way to obtain all the speed limits in km/h unit for a specific route using openstreetmap. Right now I am using annotation=speed but I don't understand the result.
My API of routing is something like this:
http://127.0.0.1:5000/route/v1/driving/72.860856,19.198877;72.860084,19.195128?steps=true&alternatives=false&geometries=geojson&annotations=speed

weight: 102,
distance: 1278.3,
annotation: {
speed: [
14.3,
14.4,
14.4,
14.3,
14.4,
14.1,
14.6,
14.5,
11.2,
11.1,
11,
11.2,
15.6,
11,
11.1,
11.1,
10.8,
11.3,
14.8,
15.6,
14.9,
14.1,
14.5,
14.4
]
},
summary: "Western Express Highway, Datta Mandir Road",
duration: 102
}

Anyone develop something similar, or does anything like this already exist?

Thanks!

[parsispresswala]

I got the answer. The given speed is of m/s unit and we need to convert it in km/h.
1 m/s = 3.4 km/h.

[danpat]

@parsispresswala Note that the speed value returned by OSRM is the speed we decide for routing, not exactly the maxspeed= tag from OSM. The speed values are decided by the car.lua script when parsing the OSM tags - maxspeed= is considered, but we rarely use its value exactly.

In order to fetch the actual maxspeed= data, you would need to use something like annotations=nodes in combination with https://github.com/mapbox/route-annotator to fetch the OSM tag information for the route after the route is found.

[parsispresswala]

@danpat Thanks for tip.

[parsispresswala]

Hello,
I find this link for speed limit.
https://help.openstreetmap.org/questions/32644/determining-speed-limits-for-given-route

Can I get speed limit of route by changing some code in car.lua profile? If yes, what changes do I have to made?

[datwelk]

@danpat is https://github.com/mapbox/route-annotator also how Mapbox Directions annotates the response with a maxspeed array (mapbox/mapbox-directions-swift#367)?

[pavlo-tk]

Hey guys,

Allow me to squeeze in here with a related question.

I'm trying to get speed limits (used by OSRM, don't need exact maxspeed) for each of the steps along the route.

Here is a very short route I'm using: http://router.project-osrm.org/route/v1/driving/-88.900584,42.225831;-88.881613,42.233121?steps=true&annotations=speed

There are 4 steps and 9 locations if you decode the geometry value (I use https://google-developers.appspot.com/maps/documentation/utilities/polyline-utility/polylineutility).

The annotation -> speed returns 43 entries with speed values, similar to the one parsispresswala showed.
So, I'm struggling to correlate those 43 speed values with 4 steps along the route. Can't understand which values are related to which steps.

What I want to achieve is to relate speed values to each of the steps. Like:

• Step 1: 17m/s
• Step 2: 20m/s
• Step 3: 13m/s
• Step 4: 30m/s

Any advice on how to read and interpret that annotation -> speed array?
Thank you in advance!

[mohd-akram]

@parsispresswala 1 m/s = 3.6 km/h

@pavlo-tk Use the geometry in the step and ignore repeated coordinates. You can get decoded values by passing geometries=geojson. There will be one less element in the annotation array, I believe this is because the first coordinate will have a speed of 0.

[danpat]

If you just need it for each step, note that the RouteStep object has a distance and duration property - you can just do speed = step[n].distance/step[n].duration.

[amlan007]

I am using OSMBonusPack for OSM based map on Android

i am querying https://router.project-osrm.org/route/v1/driving/105.8680712896,20.9947322000;105.8922453000,21.0393411000?alternatives=true&overview=full&steps=true to get the data.

Now i want the speed limit between each node.

Can anybody guide me how to do that ?

[lukasa1993]

is there any working example how to get actual route speed limit ?

[boooch]

is there any working example how to get actual route speed limit ?

Do you finally found the solution of this ?

[lukasa1993]

is there any working example how to get actual route speed limit ?

Do you finally found the solution of this ?

no sorry