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Merge pull request #619 from isaacsas/fix_networkanalysis_latex
fix broken latex from Katex
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docs/src/catalyst_functionality/network_analysis.md

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@@ -395,27 +395,26 @@ we find
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\mathbf{x}(t) = \mathbf{x}(0) + \sum_{k=1}^K \left(\int_0^t v_k(\mathbf{x})(s) \, ds\right) \mathbf{N}_k,
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```
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which demonstrates that ``\mathbf{x}(t) - \mathbf{x}(0)`` is always given by a
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linear combination of the stochiometry vectors, i.e.
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linear combination of the stoichiometry vectors, i.e.
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```math
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\DeclareMathOperator{\span}{span}
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\mathbf{x}(t) - \mathbf{x}(0) \in \span\{\mathbf{N}_k \}.
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\mathbf{x}(t) - \mathbf{x}(0) \in \operatorname{span}\{\mathbf{N}_k \}.
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```
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In particular, this says that ``\mathbf{x}(t)`` lives in the translation of the
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``\span\{\mathbf{N}_k \}`` by ``\mathbf{x}(0)`` which we write as
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``(\mathbf{x}(0) + \span\{\mathbf{N}_k\})``. In fact, since the solution should
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stay non-negative, if we let $\bar{\mathbb{R}}_+^{M}$ denote the subset of
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vectors in $\mathbb{R}^{M}$ with non-negative components, the possible physical
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values for the solution, ``\mathbf{x}(t)``, must be in the set
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``\operatorname{span}\{\mathbf{N}_k \}`` by ``\mathbf{x}(0)`` which we write as
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``(\mathbf{x}(0) + \operatorname{span}\{\mathbf{N}_k\})``. In fact, since the
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solution should stay non-negative, if we let $\bar{\mathbb{R}}_+^{M}$ denote the
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subset of vectors in $\mathbb{R}^{M}$ with non-negative components, the possible
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physical values for the solution, ``\mathbf{x}(t)``, must be in the set
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```math
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(\mathbf{x}(0) + \span\{\mathbf{N}_k\}) \cap \bar{\mathbb{R}}_+^{M}.
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(\mathbf{x}(0) + \operatorname{span}\{\mathbf{N}_k\}) \cap \bar{\mathbb{R}}_+^{M}.
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```
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This set is called the stoichiometric compatibility class of ``\mathbf{x}(t)``.
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The key property of stoichiometric compatibility classes is that they are
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invariant under the RRE ODE's dynamics, i.e. a solution will always remain
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within the subspace given by the stoichiometric compatibility class. Finally, we
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note that the *positive* stoichiometric compatibility class generated by
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$\mathbf{x}(0)$ is just ``(\mathbf{x}(0) + \span\{\mathbf{N}_k\}) \cap
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\mathbb{R}_+^{M}``, where ``\mathbb{R}_+^{M}`` denotes the vectors in
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$\mathbf{x}(0)$ is just ``(\mathbf{x}(0) + \operatorname{span}\{\mathbf{N}_k\})
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\cap \mathbb{R}_+^{M}``, where ``\mathbb{R}_+^{M}`` denotes the vectors in
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``\mathbb{R}^M`` with strictly positive components.
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With these definitions we can now see how knowing the deficiency and weak

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