Allow for finer marking of optional parameters

Current behavior allows only for marking *all* parameters as optional,
or none.

This change checks first if all parameters are optional, keeping the old
behavior if that's the case, otherwise iterates through the parameters to
mark only those that **should** be optional from the OpenAPI spec.

Resolves: #33

Author: 0237h

packages/typed-openapi/src/map-openapi-endpoints.ts

@@ -88,15 +88,22 @@ export const mapOpenApiEndpoints = (doc: OpenAPIObject) => {
       // Make parameters optional if none of them are required
       if (params) {
         const t = createBoxFactory({}, ctx);
-        if (params.query && lists.query.length && lists.query.every((param) => !param.required)) {
-          if (!params.query) params.query = {};
-          params.query = t.reference("Partial", [t.object(params.query)]) as any;
-        }
-        if (params.path && lists.path.length && lists.path.every((param) => !param.required)) {
-          params.path = t.reference("Partial", [t.object(params.path)]) as any;
-        }
-        if (params.header && lists.header.length && lists.header.every((param) => !param.required)) {
-          params.header = t.reference("Partial", [t.object(params.header)]) as any;
+
+        let k: keyof typeof params;
+        for (k in params) {
+          if (k !== "body") {
+            if (params[k] && lists[k].length) {
+              if (lists[k].every((param) => !param.required)) {
+                params[k] = t.reference("Partial", [t.object(params[k]!)]) as any;
+              } else {
+                for (const p of lists[k]) {
+                  if (!p.required) {
+                    params[k]![p.name] = t.optional(params[k]![p.name] as any);
+                  }
+                }
+              }
+            }  
+          }
         }
 
         // No need to pass empty objects, it's confusing