Prevent error when secrets directory not found

If no secrets are found, simply returns an empty object. At least
prevents the code from exploding.

Author: mikesir87

index.js

@@ -6,14 +6,16 @@ const path = require('path');
 const SECRETS_DIR = '/run/secrets';
 const output = {};
 
-const files = fs.readdirSync(SECRETS_DIR);
+if (fs.existsSync(SECRETS_DIR)) {
+  const files = fs.readdirSync(SECRETS_DIR);
 
-files.forEach(function(file, index) {
-  const fullPath = path.join(SECRETS_DIR, file);
-  const key = file;
-  const data = fs.readFileSync(fullPath, 'utf8').toString().trim();
+  files.forEach(function(file, index) {
+    const fullPath = path.join(SECRETS_DIR, file);
+    const key = file;
+    const data = fs.readFileSync(fullPath, 'utf8').toString().trim();
 
-  output[key] = data;
-});
+    output[key] = data;
+  });
+}
 
 module.exports = output;