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Recall that we can relate the Fermi energy $E_F = \frac{\hbar^2}{2m}(3\pi^2n)^{2/3}$ to the Fermi temperature:
\begin{equation}
k_B T_F = \frac{\hbar^2}{2m}(3\pi^2n)^{2/3}
\end{equation}
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