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Table.where()

David Fahlander edited this page Nov 25, 2016 · 15 revisions

Start filtering the object store by creating a WhereClause instance.

Syntax

table.where(indexOrPrimaryKey)

// Dexie 2.0.0:
table.where(keyPathArray);
table.where({keyPath1: value1, keyPath2: value2, ...});

Parameters

indexOrPrimaryKey: String Name of an index or primary key registered in Version.stores(). The special string ":id" represents the primary key.
keyPathArray Strings identifying keyPaths to filter on. Must match a compound index or primary key.
{keyPath1: value1, keyPath2, value2...} Equality criterias to match

Description

If a string, or array of strings was provided (indexes or primary keys), this method returns a WhereClause based on given index(es) or primary key(s). The returned WhereClause can be used to build a query on how to extract objects from the database using any of the methods in WhereClause. An array of strings represents [compound indexes](Compound Index).

If a plain object containing criterias was provided, this method returns a Collection filtered using given criterias. If providing a single criteria, the keyPath must match with an index. If providing multiple criterias, it is recommended to have a [compound index](Compound Index) containing all of the keyPath (in arbritary order), but it is not required. If no [compound index](Compound Index), at least one of the keyPaths must match a simple index. If Dexie.debug=true and not having compound index of all provided keyPaths, a console.warn() will give a hint on how to index this query properly.

Return Value

WhereClause if string was provided

Collection if object was provided.

Sample

Find friends named david, ignoring case

db.friends.where("name").equalsIgnoreCase("david").each(function (friend) {
    console.log("Found: " + friend.name + ". Phone: " + friend.phoneNumber);
}).catch(function (error) {
    console.error(error);
});

Find friends named David with age between 23 and 43

db.friends.where(["name", "age"])
  .between(["David", 23], ["David", 43], true, true)
  .each(friend => {
      console.log("Found David, 43: " + JSON.stringify(friend));
  }).catch(error => {
      console.error(error.stack || error);
  });

Find a friend named David with age 43

db.friends.where({name: "David", age: 43}).first(friend => {
    console.log("Found David, 43: " + JSON.stringify(friend));
}).catch(error => {
    console.error(error.stack || error);
});

See Also

WhereClause

Collection

API-Reference#query-items

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