Skip to content

Commit 9799fe5

Browse files
yanglbmeyanglbme
committed
feat: update lc problems
1 parent 5f6a3af commit 9799fe5

File tree

6 files changed

+251
-0
lines changed

6 files changed

+251
-0
lines changed

‎solution/3100-3199/3156.Employee Task Duration and Concurrent Tasks/README.md

Lines changed: 124 additions & 0 deletions
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,124 @@
1+
---
2+
comments: true
3+
difficulty: 困难
4+
edit_url: https://github.com/doocs/leetcode/edit/main/solution/3100-3199/3156.Employee%20Task%20Duration%20and%20Concurrent%20Tasks/README.md
5+
---
6+
7+
<!-- problem:start -->
8+
9+
# [3156. 员工任务持续时间和并发任务 🔒](https://leetcode.cn/problems/employee-task-duration-and-concurrent-tasks)
10+
11+
[English Version](/solution/3100-3199/3156.Employee%20Task%20Duration%20and%20Concurrent%20Tasks/README_EN.md)
12+
13+
## 题目描述
14+
15+
<!-- description:start -->
16+
17+
<p>表：<code>Tasks</code></p>
18+
19+
<pre>
20+
+---------------+----------+
21+
| Column Name | Type |
22+
+---------------+----------+
23+
| task_id | int |
24+
| employee_id | int |
25+
| start_time | datetime |
26+
| end_time | datetime |
27+
+---------------+----------+
28+
(task_id, employee_id) 是这张表的主键。
29+
这张表的每一行包含任务标识，员工标识和每个任务的开始和结束时间。
30+
</pre>
31+
32+
<p>编写一个解决方案来查找 <strong>每个</strong> 员工的任务 <strong>总持续时间</strong> 以及员工在任何时间点处理的 <strong>最大并发任务数</strong>。总时长应该 <strong>舍入</strong> 到最近的 <strong>整小时</strong>。</p>
33+
34+
<p>返回结果表以&nbsp;<code>employee_id</code><strong> <em>升序</em></strong><em>&nbsp;排序。</em></p>
35+
36+
<p>结果格式如下所示。</p>
37+
38+
<p>&nbsp;</p>
39+
40+
<p><strong class="example">示例：</strong></p>
41+
42+
<div class="example-block">
43+
<p><strong>输入：</strong></p>
44+
45+
<p>Tasks 表：</p>
46+
47+
<pre class="example-io">
48+
+---------+-------------+---------------------+---------------------+
49+
| task_id | employee_id | start_time | end_time |
50+
+---------+-------------+---------------------+---------------------+
51+
| 1 | 1001 | 2023-05-01 08:00:00 | 2023-05-01 09:00:00 |
52+
| 2 | 1001 | 2023-05-01 08:30:00 | 2023-05-01 10:30:00 |
53+
| 3 | 1001 | 2023-05-01 11:00:00 | 2023-05-01 12:00:00 |
54+
| 7 | 1001 | 2023-05-01 13:00:00 | 2023-05-01 15:30:00 |
55+
| 4 | 1002 | 2023-05-01 09:00:00 | 2023-05-01 10:00:00 |
56+
| 5 | 1002 | 2023-05-01 09:30:00 | 2023-05-01 11:30:00 |
57+
| 6 | 1003 | 2023-05-01 14:00:00 | 2023-05-01 16:00:00 |
58+
+---------+-------------+---------------------+---------------------+
59+
</pre>
60+
61+
<p><strong>输出：</strong></p>
62+
63+
<pre class="example-io">
64+
+-------------+------------------+----------------------+
65+
| employee_id | total_task_hours | max_concurrent_tasks |
66+
+-------------+------------------+----------------------+
67+
| 1001 | 6 | 2 |
68+
| 1002 | 2 | 2 |
69+
| 1003 | 2 | 1 |
70+
+-------------+------------------+----------------------+
71+
</pre>
72+
73+
<p><strong>解释：</strong></p>
74+
75+
<ul>
76+
<li>对于员工 ID 1001：
77+
<ul>
78+
<li>任务 1 和任务 2 从 08:30 到&nbsp;09:00 重叠（30 分钟）。</li>
79+
<li>任务 7 持续时间为 150 分钟（2 小时 30 分钟）。</li>
80+
<li>总工作小时：60（任务 1）+ 120（任务 2）+ 60（任务&nbsp;3）+ 150（任务 7）- 30（重叠）= 360 分钟 = 6 小时。</li>
81+
<li>最大并发任务：2 （重叠期间）。</li>
82+
</ul>
83+
</li>
84+
<li>对于员工 ID 1002：
85+
<ul>
86+
<li>任务 4 和任务 5 从 09:30 到&nbsp;10:00 重叠（30 分钟）。</li>
87+
<li>总工作时间：60 （任务&nbsp;4）+ 120（任务 5）- 30（重叠）= 150 分钟 = 2 小时 30 分钟。</li>
88+
<li>总工作小时：（舍入后）：2 小时。</li>
89+
<li>最大并发任务：2 （重叠期间）。</li>
90+
</ul>
91+
</li>
92+
<li>对于员工 ID 1003：
93+
<ul>
94+
<li>没有重叠的工作。</li>
95+
<li>总工作时间：120 分钟 = 2 小时。</li>
96+
<li>最大并发任务：1。</li>
97+
</ul>
98+
</li>
99+
</ul>
100+
101+
<p><b>注意：</b>输出表以 employee_id 升序排序。</p>
102+
</div>
103+
104+
<!-- description:end -->
105+
106+
## 解法
107+
108+
<!-- solution:start -->
109+
110+
### 方法一
111+
112+
<!-- tabs:start -->
113+
114+
#### MySQL
115+
116+
```sql
117+
118+
```
119+
120+
<!-- tabs:end -->
121+
122+
<!-- solution:end -->
123+
124+
<!-- problem:end -->

‎solution/3100-3199/3156.Employee Task Duration and Concurrent Tasks/README_EN.md

Lines changed: 123 additions & 0 deletions
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,123 @@
1+
---
2+
comments: true
3+
difficulty: Hard
4+
edit_url: https://github.com/doocs/leetcode/edit/main/solution/3100-3199/3156.Employee%20Task%20Duration%20and%20Concurrent%20Tasks/README_EN.md
5+
---
6+
7+
<!-- problem:start -->
8+
9+
# [3156. Employee Task Duration and Concurrent Tasks 🔒](https://leetcode.com/problems/employee-task-duration-and-concurrent-tasks)
10+
11+
[中文文档](/solution/3100-3199/3156.Employee%20Task%20Duration%20and%20Concurrent%20Tasks/README.md)
12+
13+
## Description
14+
15+
<!-- description:start -->
16+
17+
<p>Table: <code>Tasks</code></p>
18+
19+
<pre>
20+
+---------------+----------+
21+
| Column Name | Type |
22+
+---------------+----------+
23+
| task_id | int |
24+
| employee_id | int |
25+
| start_time | datetime |
26+
| end_time | datetime |
27+
+---------------+----------+
28+
(task_id, employee_id) is the primary key for this table.
29+
Each row in this table contains the task identifier, the employee identifier, and the start and end times of each task.
30+
</pre>
31+
32+
<p>Write a solution to find the <strong>total duration</strong> of tasks for <strong>each</strong> employee and the <strong>maximum number of concurrent tasks</strong> an employee handled at <strong>any point in time</strong>. The total duration should be <strong>rounded down</strong> to the nearest number of <strong>full hours</strong>.</p>
33+
34+
<p>Return <em>the result table ordered by</em>&nbsp;<code>employee_id</code><strong> <em>ascending</em></strong><em> order</em>.</p>
35+
36+
<p>The result format is in the following example.</p>
37+
38+
<p>&nbsp;</p>
39+
<p><strong class="example">Example:</strong></p>
40+
41+
<div class="example-block">
42+
<p><strong>Input:</strong></p>
43+
44+
<p>Tasks table:</p>
45+
46+
<pre class="example-io">
47+
+---------+-------------+---------------------+---------------------+
48+
| task_id | employee_id | start_time | end_time |
49+
+---------+-------------+---------------------+---------------------+
50+
| 1 | 1001 | 2023-05-01 08:00:00 | 2023-05-01 09:00:00 |
51+
| 2 | 1001 | 2023-05-01 08:30:00 | 2023-05-01 10:30:00 |
52+
| 3 | 1001 | 2023-05-01 11:00:00 | 2023-05-01 12:00:00 |
53+
| 7 | 1001 | 2023-05-01 13:00:00 | 2023-05-01 15:30:00 |
54+
| 4 | 1002 | 2023-05-01 09:00:00 | 2023-05-01 10:00:00 |
55+
| 5 | 1002 | 2023-05-01 09:30:00 | 2023-05-01 11:30:00 |
56+
| 6 | 1003 | 2023-05-01 14:00:00 | 2023-05-01 16:00:00 |
57+
+---------+-------------+---------------------+---------------------+
58+
</pre>
59+
60+
<p><strong>Output:</strong></p>
61+
62+
<pre class="example-io">
63+
+-------------+------------------+----------------------+
64+
| employee_id | total_task_hours | max_concurrent_tasks |
65+
+-------------+------------------+----------------------+
66+
| 1001 | 6 | 2 |
67+
| 1002 | 2 | 2 |
68+
| 1003 | 2 | 1 |
69+
+-------------+------------------+----------------------+
70+
</pre>
71+
72+
<p><strong>Explanation:</strong></p>
73+
74+
<ul>
75+
<li>For employee ID 1001:
76+
<ul>
77+
<li>Task 1 and Task 2 overlap from 08:30 to 09:00 (30 minutes).</li>
78+
<li>Task 7 has a duration of 150 minutes (2 hours and 30 minutes).</li>
79+
<li>Total task time: 60 (Task 1) + 120 (Task 2) + 60 (Task 3) + 150 (Task 7) - 30 (overlap) = 360 minutes = 6 hours.</li>
80+
<li>Maximum concurrent tasks: 2 (during the overlap period).</li>
81+
</ul>
82+
</li>
83+
<li>For employee ID 1002:
84+
<ul>
85+
<li>Task 4 and Task 5 overlap from 09:30 to 10:00 (30 minutes).</li>
86+
<li>Total task time: 60 (Task 4) + 120 (Task 5) - 30 (overlap) = 150 minutes = 2 hours and 30 minutes.</li>
87+
<li>Total task hours (rounded down): 2 hours.</li>
88+
<li>Maximum concurrent tasks: 2 (during the overlap period).</li>
89+
</ul>
90+
</li>
91+
<li>For employee ID 1003:
92+
<ul>
93+
<li>No overlapping tasks.</li>
94+
<li>Total task time: 120 minutes = 2 hours.</li>
95+
<li>Maximum concurrent tasks: 1.</li>
96+
</ul>
97+
</li>
98+
</ul>
99+
100+
<p><b>Note:</b> Output table is ordered by employee_id in ascending order.</p>
101+
</div>
102+
103+
<!-- description:end -->
104+
105+
## Solutions
106+
107+
<!-- solution:start -->
108+
109+
### Solution 1
110+
111+
<!-- tabs:start -->
112+
113+
#### MySQL
114+
115+
```sql
116+
117+
```
118+
119+
<!-- tabs:end -->
120+
121+
<!-- solution:end -->
122+
123+
<!-- problem:end -->

‎solution/DATABASE_README.md

Lines changed: 1 addition & 0 deletions
Original file line numberDiff line numberDiff line change
@@ -279,6 +279,7 @@
279279
| 3126 | [服务器利用时间](/solution/3100-3199/3126.Server%20Utilization%20Time/README.md) | `数据库` | 中等 | 🔒 |
280280
| 3140 | [连续空余座位 II](/solution/3100-3199/3140.Consecutive%20Available%20Seats%20II/README.md) | `数据库` | 中等 | 🔒 |
281281
| 3150 | [无效的推文 II](/solution/3100-3199/3150.Invalid%20Tweets%20II/README.md) | `数据库` | 简单 | 🔒 |
282+
| 3156 | [员工任务持续时间和并发任务](/solution/3100-3199/3156.Employee%20Task%20Duration%20and%20Concurrent%20Tasks/README.md) | | 困难 | 🔒 |
282283

283284
## 版权
284285

‎solution/DATABASE_README_EN.md

Lines changed: 1 addition & 0 deletions
Original file line numberDiff line numberDiff line change
@@ -277,6 +277,7 @@ Press <kbd>Control</kbd> + <kbd>F</kbd>(or <kbd>Command</kbd> + <kbd>F</kbd> on
277277
| 3126 | [Server Utilization Time](/solution/3100-3199/3126.Server%20Utilization%20Time/README_EN.md) | `Database` | Medium | 🔒 |
278278
| 3140 | [Consecutive Available Seats II](/solution/3100-3199/3140.Consecutive%20Available%20Seats%20II/README_EN.md) | `Database` | Medium | 🔒 |
279279
| 3150 | [Invalid Tweets II](/solution/3100-3199/3150.Invalid%20Tweets%20II/README_EN.md) | `Database` | Easy | 🔒 |
280+
| 3156 | [Employee Task Duration and Concurrent Tasks](/solution/3100-3199/3156.Employee%20Task%20Duration%20and%20Concurrent%20Tasks/README_EN.md) | | Hard | 🔒 |
280281

281282
## Copyright
282283

‎solution/README.md

Lines changed: 1 addition & 0 deletions
Original file line numberDiff line numberDiff line change
@@ -3166,6 +3166,7 @@
31663166
| 3153 | [所有数对中数位不同之和](/solution/3100-3199/3153.Sum%20of%20Digit%20Differences%20of%20All%20Pairs/README.md) | | 中等 | 第 398 场周赛 |
31673167
| 3154 | [到达第 K 级台阶的方案数](/solution/3100-3199/3154.Find%20Number%20of%20Ways%20to%20Reach%20the%20K-th%20Stair/README.md) | | 困难 | 第 398 场周赛 |
31683168
| 3155 | [Maximum Number of Upgradable Servers](/solution/3100-3199/3155.Maximum%20Number%20of%20Upgradable%20Servers/README.md) | | 中等 | 🔒 |
3169+
| 3156 | [员工任务持续时间和并发任务](/solution/3100-3199/3156.Employee%20Task%20Duration%20and%20Concurrent%20Tasks/README.md) | | 困难 | 🔒 |
31693170

31703171
## 版权
31713172

‎solution/README_EN.md

Lines changed: 1 addition & 0 deletions
Original file line numberDiff line numberDiff line change
@@ -3164,6 +3164,7 @@ Press <kbd>Control</kbd> + <kbd>F</kbd>(or <kbd>Command</kbd> + <kbd>F</kbd> on
31643164
| 3153 | [Sum of Digit Differences of All Pairs](/solution/3100-3199/3153.Sum%20of%20Digit%20Differences%20of%20All%20Pairs/README_EN.md) | | Medium | Weekly Contest 398 |
31653165
| 3154 | [Find Number of Ways to Reach the K-th Stair](/solution/3100-3199/3154.Find%20Number%20of%20Ways%20to%20Reach%20the%20K-th%20Stair/README_EN.md) | | Hard | Weekly Contest 398 |
31663166
| 3155 | [Maximum Number of Upgradable Servers](/solution/3100-3199/3155.Maximum%20Number%20of%20Upgradable%20Servers/README_EN.md) | | Medium | 🔒 |
3167+
| 3156 | [Employee Task Duration and Concurrent Tasks](/solution/3100-3199/3156.Employee%20Task%20Duration%20and%20Concurrent%20Tasks/README_EN.md) | | Hard | 🔒 |
31673168

31683169
## Copyright
31693170

0 commit comments

Comments
 (0)