fixed problem with user options when show method is called #257
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feimosi
reviewed
Mar 9, 2025
Comment on lines
387
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+390
| options[item] = defaults[item]; | ||
| if (!options[item]) { | ||
| options[item] = defaults[item]; | ||
| } |
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I know this is an old PR, but can you explain what it's fixing? Maybe I'm missing something, but I don't see how this code changes anything by assigning the same value twice
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