Leap Year Checker – 8086 Assembly Language Project

This project demonstrates a simple 8086 microprocessor program written in Assembly Language using TASM to determine whether a given year is a leap year or not.

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📌 Project Overview

A leap year has 366 days instead of 365, with an extra day added to February (Feb 29). This Assembly program takes a year as input and checks whether it's a leap year based on the standard rules:

• Divisible by 4
• Not divisible by 100 unless divisible by 400

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🎯 Objective

To build a microprocessor-based solution that:

• Accepts a year as input.
• Uses basic arithmetic and conditional logic to check leap year status.
• Displays the appropriate result.

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⚙️ Technologies Used

• 8086 Assembly Language
• TASM 1.7 (Turbo Assembler)
• DOS Interrupts (INT 21H)
• Windows 10 for execution

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🧑‍💻 Team Members

• Harshad Raurale
• Kaushik Shigavan
• Shrey Raut

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📥 Input Format

The user is prompted to enter a year. Input must be a 2-digit or 4-digit number using keyboard input.

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💻 Sample Code Snippet

LEA DX,MSG  
MOV AH,09H  
INT 21H     ; Display message

LEA DX,NUMBER  
MOV AH,0AH  
INT 21H     ; Accept user input

AAD         ; Convert ASCII to binary
MOV BL,04H  
DIV BL      ; Check divisibility by 4
JZ YES      ; If zero remainder, it's a leap year

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✅ Output Displays either:

YES, IT IS A LEAP YEAR

NO, IT IS NOT A LEAP YEAR