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question about function edlib_cigar_to_iterable #110

@jingangdidi

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@jingangdidi

Hi,
I have a question about function edlib_cigar_to_iterable, if edlib_cigar is 1X15=, will return [1, 1] and [6, 7], X is 6, but = not 7

def edlib_cigar_to_iterable(edlib_cigar):
    """Function that takes as input the edlib cigar and parses it to get it in a iterable manner"""
    #encoding of DNA and operations A,T,C,G,=,X,ID
    #nuc_and_ops =  np.array([1,2,3,4,5,6,7])

    length = []
    operations = []

    for i in re.findall(r'\d+[IDX=]',edlib_cigar):
        length.append(int(i[0]))           # `1X` --> i[0] is 1, `15=` --> i[0] is 1
        if i[1] == '=':
            operations.append(5)
        elif i[1] == 'X':
            operations.append(6)
        elif i[1] == 'I' or 'D':           # `15=` --> i[1] is 5, i[1] != 'I', but 'D' always True
            operations.append(7)


    return(np.array(length),np.array(operations))

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