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Anagrams
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69 lines (55 loc) · 2.38 KB
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HackerRank Problem Solving Basic Solutions
import java.io.*;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
import java.util.stream.IntStream;
public class Anagram {
public static void main(String[] args) throws IOException {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
int dictionaryCount = Integer.parseInt(bufferedReader.readLine().trim());
List<String> dictionary = IntStream.range(0, dictionaryCount).mapToObj(i -> {
try {
return bufferedReader.readLine();
} catch (IOException ex) {
throw new RuntimeException(ex);
}
}).collect(Collectors.toList());
int queryCount = Integer.parseInt(bufferedReader.readLine().trim());
List<String> query = IntStream.range(0, queryCount).mapToObj(i -> {
try {
return bufferedReader.readLine();
} catch (IOException ex) {
throw new RuntimeException(ex);
}
})
.collect(Collectors.toList());
List<Integer> result = Result.stringAnagram(dictionary, query);
bufferedWriter.write(
result.stream()
.map(Object::toString)
.collect(Collectors.joining("\n"))
+ "\n"
);
bufferedReader.close();
bufferedWriter.close();
}
static class Result {
public static List<Integer> stringAnagram(List<String> dictionary, List<String> query) {
Map<Map<Character, Long>, Long> similarAnagramCount = dictionary.stream()
.collect(Collectors.toMap(Result::frequencyMap,
e -> 1L, Long::sum));
return query.stream()
.map(Result::frequencyMap)
.map(t -> similarAnagramCount.getOrDefault(t, 0L).intValue())
.collect(Collectors.toList());
}
private static Map<Character, Long> frequencyMap(String charSequence) {
return charSequence.chars()
.mapToObj(c -> (char) c)
.collect(Collectors.groupingBy(c -> c,
Collectors.counting()));
}
}
}